25. Among p methoxyaniline and p methylaniline which one is more basic?? If we will take o methoxyaniline and o methylaniline then which one will be more basic
![Draw the products formed when p-methylaniline (p-CH3C6H4NH2) is treated with each reagent. a. HCl b. CH3COCl c. (CH3CO)2O d. excess CH3I e. (CH3)2C=O f. CH3COCl, AlCl3 g. CH3CO2H h. NaNO2, HCl i. Draw the products formed when p-methylaniline (p-CH3C6H4NH2) is treated with each reagent. a. HCl b. CH3COCl c. (CH3CO)2O d. excess CH3I e. (CH3)2C=O f. CH3COCl, AlCl3 g. CH3CO2H h. NaNO2, HCl i.](https://homework.study.com/cimages/multimages/16/part-a9016155399093072299.png)
Draw the products formed when p-methylaniline (p-CH3C6H4NH2) is treated with each reagent. a. HCl b. CH3COCl c. (CH3CO)2O d. excess CH3I e. (CH3)2C=O f. CH3COCl, AlCl3 g. CH3CO2H h. NaNO2, HCl i.
![Draw the products formed when p-methylaniline (p-CH3C6H4NH2) is treated with each reagent. a. HCl b. CH3COCl c. (CH3CO)2O d. excess CH3I e. (CH3)2C=O f. CH3COCl, AlCl3 g. CH3CO2H h. NaNO2, HCl i. Draw the products formed when p-methylaniline (p-CH3C6H4NH2) is treated with each reagent. a. HCl b. CH3COCl c. (CH3CO)2O d. excess CH3I e. (CH3)2C=O f. CH3COCl, AlCl3 g. CH3CO2H h. NaNO2, HCl i.](https://homework.study.com/cimages/multimages/16/paet-e2212304238267042554.png)
Draw the products formed when p-methylaniline (p-CH3C6H4NH2) is treated with each reagent. a. HCl b. CH3COCl c. (CH3CO)2O d. excess CH3I e. (CH3)2C=O f. CH3COCl, AlCl3 g. CH3CO2H h. NaNO2, HCl i.
![Draw the products formed when p-methylaniline (p-CH3C6H4NH2) is treated with each reagent. a. HCl b. CH3COCl c. (CH3CO)2O d. excess CH3I e. (CH3)2C=O f. CH3COCl, AlCl3 g. CH3CO2H h. NaNO2, HCl i. Draw the products formed when p-methylaniline (p-CH3C6H4NH2) is treated with each reagent. a. HCl b. CH3COCl c. (CH3CO)2O d. excess CH3I e. (CH3)2C=O f. CH3COCl, AlCl3 g. CH3CO2H h. NaNO2, HCl i.](https://homework.study.com/cimages/multimages/16/part-_ddd4640085418964775672.png)